College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 26 - Problems - Page 1012: 56


$K = \frac{p^2}{2m}$

Work Step by Step

We can use the momentum to find an expression for $v$: $p = mv$ $v = \frac{p}{m}$ We can find an expression for the kinetic energy: $K = \frac{1}{2}mv^2$ $K = \frac{1}{2}(m)(\frac{p}{m})^2$ $K = \frac{p^2}{2m}$
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