## College Physics (4th Edition)

Published by McGraw-Hill Education

# Chapter 13 - Problems - Page 496: 8

#### Answer

The other end of the system of rods moves $2.205~mm$

#### Work Step by Step

We can find the increase in length of the copper rod when it is heated: $\Delta L = \alpha~\Delta T~L$ $\Delta L = (17\times 10^{-6}~K^{-1})(150~K)(0.35~m)$ $\Delta L = 892.5\times 10^{-6}~m$ We can find the increase in length of the aluminum rod when it is heated: $\Delta L = \alpha~\Delta T~L$ $\Delta L = (25\times 10^{-6}~K^{-1})(150~K)(0.35~m)$ $\Delta L = 1312.5\times 10^{-6}~m$ We can find the total increase in length of the system: $\Delta L_{total} = 892.5\times 10^{-6}~m+1312.5\times 10^{-6}~m$ $\Delta L_{total} = 2205\times 10^{-6}~m$ $\Delta L_{total} = 2.205\times 10^{-3}~m$ $\Delta L_{total} = 2.205~mm$ The other end of the system of rods moves $2.205~mm$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.