College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 13 - Problems - Page 496: 2

Answer

(a) The temperature is $-196~^{\circ}C$ (b) The temperature is $-321^{\circ}F$

Work Step by Step

(a) We can convert the temperature to $^{\circ}C$: $C = K-273$ $C = 77-273$ $C = -196$ The temperature is $-196~^{\circ}C$ (b) We can convert the temperature to $^{\circ}F$: $F = \frac{9}{5}C+32$ $F = \frac{9}{5}(-196)+32$ $F = -321$ The temperature is $-321^{\circ}F$
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