## College Physics (4th Edition)

(a) The temperature is $29^{\circ}C$ (b) The temperature is $302~K$
(a) We can convert the temperature to $^{\circ}C$: $C = \frac{5}{9}(F-32)$ $C = \frac{5}{9}(84-32)$ $C = 29^{\circ}C$ The temperature is $29^{\circ}C$ (b) We can convert the temperature to kelvins: $K = C+273$ $K = 29+273$ $K = 302~K$ The temperature is $302~K$.