## College Physics (4th Edition)

Published by McGraw-Hill Education

# Chapter 13 - Problems - Page 496: 6

#### Answer

We can rank the slabs in order of how much their lengths increase, from greatest to smallest: $b = d = e \gt a \gt c$

#### Work Step by Step

We can find the increase in length in each case: (a) $\Delta L = \alpha~\Delta T~L$ $\Delta L = (8\times 10^{-6}~K^{-1})(20~K)(0.90~m)$ $\Delta L = 144\times 10^{-6}~m$ (b) $\Delta L = \alpha~\Delta T~L$ $\Delta L = (8\times 10^{-6}~K^{-1})(30~K)(0.90~m)$ $\Delta L = 216\times 10^{-6}~m$ (c) $\Delta L = \alpha~\Delta T~L$ $\Delta L = (8\times 10^{-6}~K^{-1})(20~K)(0.60~m)$ $\Delta L = 96\times 10^{-6}~m$ (d) $\Delta L = \alpha~\Delta T~L$ $\Delta L = (12\times 10^{-6}~K^{-1})(20~K)(0.90~m)$ $\Delta L = 216\times 10^{-6}~m$ (e) $\Delta L = \alpha~\Delta T~L$ $\Delta L = (12\times 10^{-6}~K^{-1})(30~K)(0.60~m)$ $\Delta L = 216\times 10^{-6}~m$ We can rank the slabs in order of how much their lengths increase, from greatest to smallest: $b = d = e \gt a \gt c$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.