## College Physics (4th Edition)

(a) When the temperature is $-40^{\circ}C$, which equals $-40^{\circ}F$, the numerical value of Celsius degrees equals the numerical value of Fahrenheit degrees. (b) When the temperature is $575~K$, which equals $575^{\circ}F$, the numerical value of kelvins equals the numerical value of Fahrenheit degrees.
(a) We can find the temperature when the numerical value of Celsius degrees equals the numerical value of Fahrenheit degrees: $F = \frac{9}{5}C+32$ $F = \frac{9}{5}F+32$ $\frac{4}{5}F = -32$ $F = -40$ When the temperature is $-40^{\circ}C$, which equals $-40^{\circ}F$, the numerical value of Celsius degrees equals the numerical value of Fahrenheit degrees. (b) We can find the temperature when the numerical value of kelvins equals the numerical value of Fahrenheit degrees: $F = \frac{9}{5}C+32$ $F = \frac{9}{5}(K-273.15)+32$ $F = \frac{9}{5}K-459.67$ $F = \frac{9}{5}F-459.67$ $\frac{4}{5}F = 459.67$ $F = 575$ When the temperature is $575~K$, which equals $575^{\circ}F$, the numerical value of kelvins equals the numerical value of Fahrenheit degrees.