College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 13 - Problems - Page 496: 3

Answer

(a) When the temperature is $-40^{\circ}C$, which equals $-40^{\circ}F$, the numerical value of Celsius degrees equals the numerical value of Fahrenheit degrees. (b) When the temperature is $575~K$, which equals $575^{\circ}F$, the numerical value of kelvins equals the numerical value of Fahrenheit degrees.

Work Step by Step

(a) We can find the temperature when the numerical value of Celsius degrees equals the numerical value of Fahrenheit degrees: $F = \frac{9}{5}C+32$ $F = \frac{9}{5}F+32$ $\frac{4}{5}F = -32$ $F = -40$ When the temperature is $-40^{\circ}C$, which equals $-40^{\circ}F$, the numerical value of Celsius degrees equals the numerical value of Fahrenheit degrees. (b) We can find the temperature when the numerical value of kelvins equals the numerical value of Fahrenheit degrees: $F = \frac{9}{5}C+32$ $F = \frac{9}{5}(K-273.15)+32$ $F = \frac{9}{5}K-459.67$ $F = \frac{9}{5}F-459.67$ $\frac{4}{5}F = 459.67$ $F = 575$ When the temperature is $575~K$, which equals $575^{\circ}F$, the numerical value of kelvins equals the numerical value of Fahrenheit degrees.
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