## College Physics (4th Edition)

Published by McGraw-Hill Education

# Chapter 1 - Problems: 44

#### Answer

(a) Both equations have the dimensions $\frac{kg\cdot m}{s^2}$ (b) The force unit newton has the dimensions $\frac{kg\cdot m}{s^2}$

#### Work Step by Step

(a) We can analyze the dimensions of $ma$: $kg \times \frac{m}{s^2} = \frac{kg\cdot m}{s^2}$ We can analyze the dimensions of $kx$: $\frac{kg}{s^2} \times m = \frac{kg\cdot m}{s^2}$ We can see that the dimensions are equivalent. (b) The force unit newton has the dimensions $\frac{kg\cdot m}{s^2}$

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