College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 1 - Problems - Page 20: 39


$1.7\times 10^{-10}~km^3$

Work Step by Step

We can find the volume in units of $km^3$: $V = (3.2~km)(4.0~m)(13\times 10^{-3}~mm)$ $V = (3.2~km)(4.0\times 10^{-3}~km)(13\times 10^{-9}~km)$ $V = 1.7\times 10^{-10}~km^3$
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