College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 1 - Problems - Page 20: 32


(a) $255~cm^3$ (b) $2.55\times 10^{-4}~m^3$

Work Step by Step

(a) $255~mL\times \frac{10^{-3}~L}{1~mL} \times \frac{10^3~cm^3}{1~L} = 255~cm^3$ (b) $255~cm^3\times \frac{1~m^3}{10^6~cm^3} = 255 \times 10^{-6}~m^3 = 2.55\times 10^{-4}~m^3$
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