Answer
The molecule would move a distance of 3.21 meters.
Work Step by Step
$d = vt = (459~m/s)(7.00\times 10^{-3}~s) = 3.21~m$
The molecule would move a distance of 3.21 meters.
College Physics (4th Edition)
by Giambattista, Alan; Richardson, Betty; Richardson, Robert
Published by
McGraw-Hill Education
ISBN 10:
0073512141
ISBN 13:
978-0-07351-214-3
Chapter 1 - Problems - Page 20: 38
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