College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 1 - Problems: 38

Answer

The molecule would move a distance of 3.21 meters.

Work Step by Step

$d = vt = (459~m/s)(7.00\times 10^{-3}~s) = 3.21~m$ The molecule would move a distance of 3.21 meters.
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