## College Physics (4th Edition)

(a) We can convert $5.0~cm/min$ to units of $ft/s$: $5.0~cm/min\times \frac{1~min}{60~s}\times \frac{1~in}{2.54~cm} \times \frac{1~ft}{12~in} = 0.0027~ft/s$ (b) We can convert $5.0~cm/min$ to units of $mi/h$: $5.0~cm/min\times \frac{60~min}{1~hr}\times \frac{1~in}{2.54~cm} \times \frac{1~ft}{12~in}\times \frac{1~mi}{5280~ft} = 0.0019~mi/h$