College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 1 - Problems - Page 20: 41


(a) 0.0027 ft/s (b) 0.0019 mi/h

Work Step by Step

(a) We can convert $5.0~cm/min$ to units of $ft/s$: $5.0~cm/min\times \frac{1~min}{60~s}\times \frac{1~in}{2.54~cm} \times \frac{1~ft}{12~in} = 0.0027~ft/s$ (b) We can convert $5.0~cm/min$ to units of $mi/h$: $5.0~cm/min\times \frac{60~min}{1~hr}\times \frac{1~in}{2.54~cm} \times \frac{1~ft}{12~in}\times \frac{1~mi}{5280~ft} = 0.0019~mi/h$
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