Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 8 - Exercises and Problems - Page 148: 59

Answer

a) 2,060,082 meters b) 805,145 meters

Work Step by Step

We know that the current radius of orbit is equal to its height plus the radius of the earth. Thus, we find: $ r=(6.37\times10^6)+(5.5\times10^6)=1.187\times10^7$ a) We know that the orbit changes by a factor of $1-\frac{1}{1.1^2}=.17$ We multiply this by the value of r to find: $r=\fbox{2,060,082 meters}$ b) In this problem, we need to use the equation for orbital period to find the change in radius. Since the value of T is squared and the value of r is cubed, we find that the orbit changes by a factor of $|1-\frac{1}{.9^{2/3}}|=.06783$ We multiply this by the value of r to find: $r=\fbox{805,145 meters}$
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