Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 8 - Exercises and Problems - Page 148: 65

Answer

$4.597\times10^{12} \ m$

Work Step by Step

We know that the ratios of velocities is equal to the distance away. Thus, we first find the ratios: $=\frac{38.8}{59}=.6576$ We multiply this by the maximum distance to find: $v = .6576 \times 6.99\times10^{12}=4.597\times10^{12} \ m$
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