Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 8 - Exercises and Problems - Page 148: 51

Answer

Hyperbolic

Work Step by Step

We find the escape speed: $v_{esc}=\sqrt{\frac{2GM}{r}}$ $v_{esc}=\sqrt{\frac{2(6.67\times10^{-11})(1.99\times10^{30})}{1.87\times10^{12}}}=1.19\times10^4$ Since the Comet is going faster than this, it will not return to the sun's vicinity. Thus, the motion is hyperbolic, not elliptical.
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