## Essential University Physics: Volume 1 (4th Edition)

Published by Pearson

# Chapter 8 - Exercises and Problems - Page 148: 51

Hyperbolic

#### Work Step by Step

We find the escape speed: $v_{esc}=\sqrt{\frac{2GM}{r}}$ $v_{esc}=\sqrt{\frac{2(6.67\times10^{-11})(1.99\times10^{30})}{1.87\times10^{12}}}=1.19\times10^4$ Since the Comet is going faster than this, it will not return to the sun's vicinity. Thus, the motion is hyperbolic, not elliptical.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.