## Essential University Physics: Volume 1 (4th Edition)

$T_A=8T_B$
As we know that the time period for satellite A is $T_A=2\pi\sqrt{\frac{R_A^3}{GM}}$ Similarly for satellite B $T_B=2\pi\sqrt{\frac{R_B^3}{GM}}$ Now we can find the ratio of the two satellites time period as: $\frac{T_A}{T_B}=\sqrt{\frac{R_A^3}{R_B^3}}$ Substituting $R_A=4R_B$, we obtain: $T_A=8T_B$