Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 8 - Exercises and Problems - Page 148: 49



Work Step by Step

We know that the kinetic energy is the result of a change in potential energy. Thus, in order to solve this problem, we use conservation of energy. Doing this, we find: $\frac{1}{2}mv_f^2 + U_f=\frac{1}{2}mv_0^2 +U_0$ $\frac{1}{2}mv_f^2 -\frac{GMm}{R_e+22,000}=\frac{1}{2}mv_0^2 -\frac{GMm}{r}$ Plugging in the known values, we find: $r = 4.185 \times10^{11}=2.79 \ AU$
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