Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 7 - Exercises and Problems - Page 130: 22

Answer

Please see the work below.

Work Step by Step

We know that $\Delta K=-f_k d$ This can be rearranged as: $d=\frac{\Delta K}{-f_k}$ We plug in the known values to obtain: $d=\frac{\frac{-1}{2}mv^2}{-\mu_k mg}$ $d=\frac{v^2}{2\mu g}$ $d=\frac{8.2}{2\times 0.023\times 9.8}=22.71m$
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