Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 7 - Exercises and Problems - Page 130: 18


Please see the work below.

Work Step by Step

We know that according to law of conservation of energy $\frac{1}{2}mv^2=\frac{1}{2}kx^2$ This simplifies to: $v=\sqrt{\frac{K}{m}}x$ We plug in the known values to obtain: $v=\sqrt{\frac{40000}{10000}}(25)=50\frac{m}{s} = 180 \frac{km}{h}$
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