Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 7 - Exercises and Problems - Page 130: 21

Answer

Please see the work below.

Work Step by Step

According to law of conservation of energy $mgh=\frac{1}{2}Kx^2$ This simplifies to: $K=\frac{2mgh}{x^2}$ We plug in the known values to obtain: $K=\frac{(2)(0.065)(9.8)(35)}{(0.14)^2}=2300\frac{N}{m}$
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