Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 7 - Exercises and Problems - Page 130: 10

Answer

The work done by gravity is $-mgL$ in both cases.

Work Step by Step

We know that gravity is a conservative force. Though the idea of conservative vector fields is something you will touch far more in vector calculus, the consequence is that the potential energy is path independent. In other words, it does not matter what path you take; what matters is where you start and where you end up. Thus, we can use the simple formula, U=mgh, to see that the change in potential energy is $-mgL.$
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