Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 7 - Exercises and Problems - Page 130: 15


Please see the work below.

Work Step by Step

We know that $U=\frac{1}{2}Kx^2$ This simplifies to: $U=\sqrt{\frac{2U}{K}}$ We plug in the known values to obtain: $U=\sqrt{\frac{2(210)}{1400}}=0.55m$
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