Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 6 - Exercises and Problems - Page 111: 81


The proof is below.

Work Step by Step

Work is equal to the integral of power with respect to time. Thus, we find: $W=\int P dt$ $W=\int_0^{\infty} (\frac{P_0t_0^2}{t+t_0^2}) dt$ $W=((\frac{-P_0t_0^2}{(t+t_0^2)^2})|_0^{\infty}$) We know that the infinite limit of the equation is $-P_0t_0^2$, so we know that the magnitude of the work done as time approaches infinity is $P_0t_0^2$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.