Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 6 - Exercises and Problems - Page 111: 69

Answer

$5.616\times10^{7}GW$

Work Step by Step

We can get from appendix C, the Energy content of oil= 39 kWh/gal Consumption of oil day in US $=400\times10^{6}gal$ Energy production in each day by US $=\frac{39\space kWh}{gal}\times400\times10^{6}gal$ $\space \space \space \space \space\space \space \space \space \space\space \space \space \space \space\space \space \space \space \space\space \space \space \space \space\space \space \space \space \space= 156\times10^{8}kWh$ By using conversion factors, we can change the units of the above value. $156\times10^{8}kWh=156\times10^{8}\times10^{3}\times3600\space W$ $\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space=5616\times10^{13}W$ $\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space=5.616\times10^{7}\space GW$
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