Answer
$0.17$
Work Step by Step
Here we use the equation $W=FS$ to find the value of $a$
$W=FS$
Let's plug known values into this equation.
$1.86\space kJ= \int_ {0}^{18.5}ax^{3/2}\space N\space dx\space \times 18.5\space m$
$1.86\times10^{3}kgm^{2}/s^{2}= a\space \lvert (\frac{x^{3/2+1}}{\frac{3}{2}+1})\rvert_{0}^{18.5} \times18.5\space kgm^{2}/s^{2}$
$1.86\times10^{3}=\frac{a}{2.5}\space [1472-0]\times 18.5$
$0.17=a$
