Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 6 - Exercises and Problems - Page 111: 74

Answer

$(a)\space 16.7\space J $ $(b)\space 1.4\space W$

Work Step by Step

(a) Here we use the equation $W=mgh$ to find the work done in lifting 1L of blood from the foot to the head. $W=mgh$ Let's plug known values into this equation. $W=1\space kg\times9.8\space m/s^{2}\times1.7\space m$ $W=16.7\space J$ (b) Let's take the work done by the heart = P, We can write, $p=\frac{Total\space work\space done}{Total\space time}$ Let's plug known values into this equation. $P=5\times\frac{16.7\space J}{1\space min}(\frac{1\space min}{60\space s})=1.4\space W$
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