Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 5 - Exercises and Problems - Page 90: 16


$ \theta = cos ^{-1} (580/700)=34^{\circ}$

Work Step by Step

They can cross the bridge safely. We know that the force, 700 N, times the cosine of the incline angle of the bridge gives the normal force. Thus, we see: $ F_{max}= Ncos( \theta)$ $ \theta = cos ^{-1} (F_{max}/N)$ This gives: $ \theta = cos ^{-1} (580/700)=34^{\circ}$
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