Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 5 - Exercises and Problems - Page 90: 21

Answer

Please see the work below.

Work Step by Step

We know that $F=mr\omega^2$ $F=mr(\frac{2\pi}{T})^2$ $F=\frac{4\pi^2mr}{T^2}$
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