Answer
$5.4\hat{i}-10.96\hat{j}$
Work Step by Step
We multiply the acceleration of the object by its mass to find the net force acting on it:
$F = 3.25(5.48cos38\hat{i}-5.48sin(38\hat{j}))=14.03\hat{i}-10.96\hat{j}$
We know that there is already a force of 8.63 Newtons in the x-direction, so we find:
$5.4\hat{i}-10.96\hat{j}$
