# Chapter 5 - Exercises and Problems - Page 90: 11

$5.4\hat{i}-10.96\hat{j}$

#### Work Step by Step

We multiply the acceleration of the object by its mass to find the net force acting on it: $F = 3.25(5.48cos38\hat{i}-5.48sin(38\hat{j}))=14.03\hat{i}-10.96\hat{j}$ We know that there is already a force of 8.63 Newtons in the x-direction, so we find: $5.4\hat{i}-10.96\hat{j}$

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