## Essential University Physics: Volume 1 (4th Edition) Clone

$\theta = 22.4 ^{\circ}$
For this to happen, we need the force in the downward direction to be $3.7m/s^2$ We know that: $g_{mars}=g_{earth}sin( \theta)$ This gives: $\theta = sin^{-1}( \frac{g_{mars}}{g_{earth}})=sin^{-1}( .378)$ $\theta = 22.4 ^{\circ}$