Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 5 - Exercises and Problems - Page 90: 14

Answer

Please see the work below.

Work Step by Step

We know that $a=gsin(\theta)=9.8sin(24)=3.986\frac{m}{s^2}$ $d=(\frac{1}{2})at^2$ This simplifies to: $t=\sqrt{\frac{2d}{a}}=\sqrt{\frac{(2)(1300)}{3.986}}=26s$
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