Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 3 - Exercises and Problems - Page 51: 66

Answer

$v_0 = \sqrt{2gh +\frac{R^2g}{8h} }$

Work Step by Step

We know from the values of the x and y components of velocity that: $v_0 = \sqrt{2gh +\frac{R^2g^2}{8gh} }$ This simplifies to: $v_0 = \sqrt{2gh +\frac{R^2g}{8h} }$
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