Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 3 - Exercises and Problems - Page 51: 66


$v_0 = \sqrt{2gh +\frac{R^2g}{8h} }$

Work Step by Step

We know from the values of the x and y components of velocity that: $v_0 = \sqrt{2gh +\frac{R^2g^2}{8gh} }$ This simplifies to: $v_0 = \sqrt{2gh +\frac{R^2g}{8h} }$
This answer is currently locked

Someone from the community is currently working feverishly to complete this textbook answer. Don’t worry, it shouldn’t be long.