Answer
$v_0 = \sqrt{2gh +\frac{R^2g}{8h} }$
Work Step by Step
We know from the values of the x and y components of velocity that:
$v_0 = \sqrt{2gh +\frac{R^2g^2}{8gh} }$
This simplifies to:
$v_0 = \sqrt{2gh +\frac{R^2g}{8h} }$
Essential University Physics: Volume 1 (4th Edition) Clone
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 3 - Exercises and Problems - Page 51: 66
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