Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 3 - Exercises and Problems - Page 51: 46


Please see the work below.

Work Step by Step

We know that $A_x+B_x=0$ $|Acos (35)|+B_x=0$ $(1.0)cos(35)+B_x=0$ $B_x=-0.8192m$ We can find the direction of B as $\theta=180-cos^{-1}(\frac{B_x}{B})$ $\theta=180-cos^{-1}(\frac{0.8192}{1.8})=117^{\circ}$
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