## Essential University Physics: Volume 1 (4th Edition)

We know that $A_x+B_x=0$ $|Acos (35)|+B_x=0$ $(1.0)cos(35)+B_x=0$ $B_x=-0.8192m$ We can find the direction of B as $\theta=180-cos^{-1}(\frac{B_x}{B})$ $\theta=180-cos^{-1}(\frac{0.8192}{1.8})=117^{\circ}$