Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 3 - Exercises and Problems - Page 51: 42

Answer

11.88 hours

Work Step by Step

We know the equation for the period of an orbit: $T=\sqrt{\frac{4\pi^2 r}{a}}$ We know the value of "a" is: $a = 9.81(.058)=.5684$ We use the known values, adding the radius of the earth to the altitude, to find: $T=\sqrt{\frac{4\pi^2 ((2+.6371)\times10^7m)}{.5684}}=42,773s=\fbox{11.88 hours}$
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