Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 3 - Exercises and Problems - Page 51: 57


Please see the work below.

Work Step by Step

We know that $a=\frac{v^2}{r}$ This can be rearranged as $r=\frac{v^2}{a}$ We plug in the known values to obtain: $r=\frac{(19.44)^2}{3.92}=96m$
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