Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 3 - Exercises and Problems - Page 51: 49

Answer

a) $ \frac{4c}{3d}$ b) $t = \frac{c}{3d}$

Work Step by Step

a) The particle is moving in the x-direction when the y-component is 0. Thus, we find: $4ct -3dt^2 =0\\4ct = 3dt^2 \\ 4c = 3dt \\ t = \frac{4c}{3d}$ a) The particle is moving in the y-direction when the x-component is 0. Thus, we find: $2ct - 6dt^2 = 0 \\ 2ct = 6dt^2 \\ t = \frac{c}{3d}$
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