Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 2 - Exercises and Problems - Page 31: 50

Answer

$\frac{6V}{5}$

Work Step by Step

Please see the attached image first. Here, this question asked the average speed, and let's write the equation for average speed as follows. $$Average\space speed= \frac{Total\space displacement}{Total\space time}-(1)$$ From equation (1) and the notations in the attached image, we can write, $Average\space speed=\frac{S}{t1+t2}-(2)$ To find this value we have to find t1, and t2 in terms of S. Let's consider the figure (1) and apply equation $S=Ut+\frac{1}{2}at^{2}$ to the object. $\rightarrow S=Ut+\frac{1}{2}at^{2}$ $\frac{S}{3}=2Vt1+\frac{1}{2}(0)(t1)^{2}$ $t1=\frac{S}{6V}$ Let's consider figure (2) and apply equation $S=Ut+\frac{1}{2}at^{2}$ to the object. $\rightarrow S=Ut+\frac{1}{2}at^{2}$ $\frac{2S}{3}=Vt2+\frac{1}{2}(0)(t2)^{2}$ $t2=\frac{2S}{3V}$ $(2)\space=\gt$ $Average\space speed=\frac{S}{t1+t2}=\frac{S}{\frac{S}{6V}+\frac{2S}{3V}}=\frac{6V}{5}$
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