Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 2 - Exercises and Problems - Page 31: 41

Answer

$a=53.777ft/s^2$

Work Step by Step

All we have to use is the slightly uncommon formula for a constant acceleration system. That is, $v_f^2 = v_i^2 +2al.$ Substituting the given values, $$a=\frac{(50mi/h)^2}{2\cdot 100ft}=\frac{(73.3333ft/s)^2}{100ft}=53.777ft/s$$
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