Answer
(a) 5.4 m
(b) 10.29 m/s
Work Step by Step
Please see the attached image first.
(a) We know that the height of the cliff = displacement of the diver. So, we can apply the equation $S=Ut +\frac{1}{2}at^{2}$to find the displacement of the diver.
$\downarrow S=Ut +\frac{1}{2}at^{2}$
Let's plug known values into this equation.
$h=(0)\times(1.05\space s)+ \frac{1}{2}(9.8\space m/s^{2})\times(1.05\space s)^{2}$
$h=4.9\times1.1025\space m$
$h=5.4\space m$
(b) To find the speed at the water of the diver, we can apply the equation $V=U+at$
$\downarrow V=U+at$
Let's plug known values into this equation.
$V=0+9.8\space m/s^{2}\times1.05\space s$
$V=10.29\space m/s$
Speed of the diver = $10.29\space m/s$
