Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 2 - Exercises and Problems - Page 31: 35

Answer

$h_{max}$ = 3.2m

Work Step by Step

the maximum height is leading to final speed of 8m/s when released from rest $h_{max}$ = $\frac{v_{f}^{2}-v_{i}^{2}}{2a}$ = $\frac{(8m/s)^{2}}{2 \times 10 m/s^{2}}$ = 3.2m
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