Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 2 - Exercises and Problems - Page 31: 57

Answer

Please see the work below.

Work Step by Step

We know that $\Delta d=142-23=119m$ Now $a=\frac{v^2-v_{\circ}^2}{2\Delta d}$ $a=\frac{(0.75)^2-(32)^2}{2.119}=4.3\frac{m}{s^2}$
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