Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 16 - Exercises and Problems - Page 310: 51


Please see the work below.

Work Step by Step

We know that $Q=mc\Delta T$ We plug in the known values to obtain: $Q=(0.330)(4184)(100-10)$ $Q=124300J$ Now we can find the time as $t=\frac{Q}{P}$ $t=\frac{124300}{900}$ $t=140s = 2.3 min$
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