Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 16 - Exercises and Problems - Page 310: 38

Answer

We can use the principle of conservation of energy to solve this problem. The energy lost by the copper is equal to the energy gained by the zinc. The formula for the energy transferred is: Q = mcpΔT Where Q is the amount of heat transferred, m is the mass of the object, cp is the specific heat capacity, and ΔT is the change in temperature. Let's first calculate the energy transferred from the copper to the zinc: Q1 = m1 * cp1 * ΔT1 Q1 = 755 kg * 572 J/kg·K * (1350°C - 1170°C) Where cp1 is the specific heat capacity of copper. The energy gained by the zinc is: Q2 = m2 * cp2 * ΔT2 Q2 = m2 * 497 J/kg·K * (1170°C - 469°C) Where cp2 is the specific heat capacity of zinc. Since there is no heat loss, the energy gained by the zinc is equal to the energy lost by the copper: Q1 = Q2 755 kg * 572 J/kg·K * (1350°C - 1170°C) = m2 * 497 J/kg·K * (1170°C - 469°C) Simplifying the equation, we get: 755 * 572 * 180 = m2 * 497 * 701 Solving for m2, we get: m2 = 962 kg Therefore, the mass of zinc added is 962 kg. The total mass of the alloy is: m_total = m_copper + m_zinc m_total = 755 + 962 m_total = 1717 kg The percent of the alloy's mass that is zinc is: percent_zinc = m_zinc / m_total * 100 percent_zinc = 962 / 1717 * 100 percent_zinc = 56.0% Therefore, approximately 56.0% of the alloy's mass is zinc.

Work Step by Step

We can use the principle of conservation of energy to solve this problem. The energy lost by the copper is equal to the energy gained by the zinc. The formula for the energy transferred is: Q = mcpΔT Where Q is the amount of heat transferred, m is the mass of the object, cp is the specific heat capacity, and ΔT is the change in temperature. Let's first calculate the energy transferred from the copper to the zinc: Q1 = m1 * cp1 * ΔT1 Q1 = 755 kg * 572 J/kg·K * (1350°C - 1170°C) Where cp1 is the specific heat capacity of copper. The energy gained by the zinc is: Q2 = m2 * cp2 * ΔT2 Q2 = m2 * 497 J/kg·K * (1170°C - 469°C) Where cp2 is the specific heat capacity of zinc. Since there is no heat loss, the energy gained by the zinc is equal to the energy lost by the copper: Q1 = Q2 755 kg * 572 J/kg·K * (1350°C - 1170°C) = m2 * 497 J/kg·K * (1170°C - 469°C) Simplifying the equation, we get: 755 * 572 * 180 = m2 * 497 * 701 Solving for m2, we get: m2 = 962 kg Therefore, the mass of zinc added is 962 kg. The total mass of the alloy is: m_total = m_copper + m_zinc m_total = 755 + 962 m_total = 1717 kg The percent of the alloy's mass that is zinc is: percent_zinc = m_zinc / m_total * 100 percent_zinc = 962 / 1717 * 100 percent_zinc = 56.0% Therefore, approximately 56.0% of the alloy's mass is zinc.
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