## Essential University Physics: Volume 1 (4th Edition)

We use known equations to obtain: a) $Q = ms\Delta T \\ Q = (.8)(75)(386) = 23 \ kJ$ b) $\Delta Q = ms\Delta T + m_ws_w\Delta T \\ \Delta Q = 23 \ kJ + 1(4184)(75) \\ \Delta Q = 337 \ kJ$ c) $\Delta Q = ms\Delta T + m_ws_w\Delta T \\ \Delta Q = 23 + 4(140)(75) = 65 \ kJ$