Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 16 - Exercises and Problems - Page 310: 49

Answer

a) 23 kJ b) 337 kJ c) 65 kJ

Work Step by Step

We use known equations to obtain: a) $ Q = ms\Delta T \\ Q = (.8)(75)(386) = 23 \ kJ $ b) $\Delta Q = ms\Delta T + m_ws_w\Delta T \\ \Delta Q = 23 \ kJ + 1(4184)(75) \\ \Delta Q = 337 \ kJ$ c) $\Delta Q = ms\Delta T + m_ws_w\Delta T \\ \Delta Q = 23 + 4(140)(75) = 65 \ kJ$
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