## Essential University Physics: Volume 1 (4th Edition)

We know: $\Delta Q = m_wS_w\Delta T_w$ $\Delta Q = m_xS_x\Delta T_x$ Setting these equal to each other and simplifying gives: $S_x = \frac{\Delta T_w S_w m_w}{\Delta T_x m_x} \\ S_x = \frac{100\times10^{-3}\times 4184\times12}{100\times10^{-3}\times 56} = 900 \frac{J}{kg K }$ The material is $\fbox{Aluminum.}$ We now find the value of the heat flow rate: $= \frac{\Delta Q}{\Delta t} = \frac{5020.8}{60}=\fbox{83.68 W}$