Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 16 - Exercises and Problems - Page 310: 44


$55.2 \ kPa$

Work Step by Step

We know the following equation: $\frac{P_2}{P_1}=\frac{T_2}{T_1}$ Thus, we find: $\frac{274.16}{273.16}=\frac{P_2}{55} \\ P_2 = 55.2 \ kPa$
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