Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 15 - Exercises and Problems - Page 291: 69


Yes, it could.

Work Step by Step

We first find the wind output per unit area: $P=\frac{1}{2}\rho v^3 $ $ P = \frac{1}{2}(.3)(1.2)(12^2)=25.92 \ W$ We multiply this by the overall area: $P_t=25.92\times \pi \times (\frac{95}{2})^2 \times 800=147 \ GW $ Thus, it could replace the power plant.
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