Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 15 - Exercises and Problems - Page 291: 62


$ \rho = 6 \times 10^2 \ kg/m^2$

Work Step by Step

We simplify the equation for flow speed in order to isolate density. Doing this, we obtain: $ \rho = \frac{2\Delta P}{((\frac{A_1}{A_2})^2 - 1)v^2}$ We know that $\frac{A_1}{A_2}=4$. Plugging this in, the pressure as $16\times 10^3$, and the velocity as 1.9 meters per second, we obtain: $ \rho = 6 \times 10^2 \ kg/m^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.