Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 15 - Exercises and Problems - Page 291: 54

Answer

9 children

Work Step by Step

We can write, The float's weight is $W_{f}$ = 20g The weight of the displaced water is $W_{w}=m_{w}g=\rho_{water}V_{sub}g$ By Archimedes' principle, $W_{w}$ is equal in magnitude to the buoyancy force, which balances gravity when the slab is in equilibrium. Let's find the minimum weight required to fully merge the float. $W=\rho_{water}V_{sub}g=1000\space kg/m^{3}\times1.8\times2.4\times0.1\space m^{3}g\space m/s^{2}$ $W=432g\space N$ Total weight of children = (432g - 20g)N = 412g N Nos. of children required to $=\frac{412g}{50g}=8.24$ fully emerge the boat So 9 children required to fully emerge the boat
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