## Essential University Physics: Volume 1 (4th Edition) Clone

$14.6 \ kg$
We find the following equation for the mass it can support: $m = \frac{\mu P\pi d^2}{4g}$ Plugging in the known values, we obtain: $m = \frac{(.72)(1.01\times10^5)(\pi)(.05)^2}{4(9.81)}=14.6 \ kg$