Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 15 - Exercises and Problems - Page 291: 61

Answer

70 percent

Work Step by Step

We adjust the equation found in example 15.7 to find: $\frac{A_2}{A_1}=\sqrt{\frac{2\Delta P}{\rho (v_1)^2}+1}$ $\frac{A_2}{A_1}=\sqrt{\frac{2(.05)(10,000)}{(1060) (.3)^2}+1}=3.39$ Thus, we find how much is not obstructed: $\frac{1}{3.39}=.295=29.5$% Thus, 70% of the artery is obstructed.
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